R(p)=-8p^2+16000p

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Solution for R(p)=-8p^2+16000p equation:



(R)=-8R^2+16000R
We move all terms to the left:
(R)-(-8R^2+16000R)=0
We get rid of parentheses
8R^2-16000R+R=0
We add all the numbers together, and all the variables
8R^2-15999R=0
a = 8; b = -15999; c = 0;
Δ = b2-4ac
Δ = -159992-4·8·0
Δ = 255968001
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$R_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$R_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{255968001}=15999$
$R_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15999)-15999}{2*8}=\frac{0}{16} =0 $
$R_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15999)+15999}{2*8}=\frac{31998}{16} =1999+7/8 $

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